A) 1.8
B) 1.43
C) 2
D) None of these
Correct Answer: B
Solution :
The equivalent refractive index of combination of slabs for normal incidence is \[\mu =\frac{\Sigma \,{{t}_{i}}}{\Sigma \frac{{{t}_{i}}}{{{\mu }_{\,i}}}}\] In this case, \[\mu =\frac{{{t}_{1}}+{{t}_{2}}}{\frac{{{t}_{1}}}{{{\mu }_{1}}}+\frac{{{t}_{2}}}{{{\mu }_{2}}}}\] \[=\frac{10+15}{\frac{10}{4/3}+\frac{15}{3/2}}\] \[=\frac{25}{7.5+10}=\frac{25}{17.5}\] = 1.43
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