A) \[\text{ta}{{\text{n}}^{-\text{1}}}\text{ }\left( \pi \right)\]
B) \[\text{ta}{{\text{n}}^{-\text{1}}}\text{ }\left( \frac{\pi }{2} \right)\]
C) \[\text{ta}{{\text{n}}^{-\text{1}}}\text{ }\left( \frac{\pi }{4} \right)\]
D) \[\text{ta}{{\text{n}}^{-\text{1}}}\text{ }\left( \frac{\pi }{3} \right)\]
Correct Answer: A
Solution :
\[\tan \phi =\frac{{{X}_{L}}}{R}\] and \[{{X}_{L}}=\omega L=2\pi fL\] \[=2\pi \times 50\times 0.01=\pi \,\Omega \] Also, \[R=1\Omega \] \[\phi ={{\tan }^{-1}}(\pi )\]
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