AMU Medical AMU Solved Paper-2006

  • question_answer
    The couple acting on a magnet of length10 cm  and pole strength 15 Am, kept in a field of \[\text{B}=\text{2}\times \text{1}{{0}^{-\text{5}}}\text{ T},\]at an angle of 30° is

    A)  \[\text{1}.\text{5}\times \text{l}{{\text{0}}^{-5}}\text{N}-\text{m}\]   

    B)  \[\text{1}.\text{5}\times \text{l}{{\text{0}}^{-3}}\text{N}-\text{m}\]

    C)  \[\text{1}.\text{5}\times \text{l}{{\text{0}}^{-2}}\text{N}-\text{m}\]   

    D)  \[\text{1}.\text{5}\times \text{l}{{\text{0}}^{-6}}\text{N}-\text{m}\]

    Correct Answer: A

    Solution :

                     \[C=MB\,\sin \theta \] \[=(m\times 2l)\times 2\times {{10}^{-5}}\times \sin {{30}^{o}}\] \[=15\times 10\times {{10}^{-2}}\times 2\times {{10}^{-5}}\times \frac{1}{2}\] \[=1.5\times {{10}^{-5}}N-m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner