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AMU Medical AMU Solved Paper-2006

  • question_answer
    A body of mass m rises to height h = R/S from earths surface, where R is earths radius. Ifg is acceleration due to gravity at earths surface, the increase in potential energy is

    A)  \[mgh\]                              

    B)  \[\frac{4}{5}mgh\]

    C)   \[\frac{5}{6}mgh\]                        

    D)  \[\frac{6}{7}mgh\]

    Correct Answer: C

    Solution :

                     \[\Delta U=\frac{mgh}{1+h/R}\] Substituting R = 5h, we get                 \[\Delta U=\frac{mgh}{1+1/5}=\frac{5}{6}mgh\]


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