AMU Medical AMU Solved Paper-2006

  • question_answer
    First \[C{{O}_{2}}\]acceptor in \[{{C}_{4}}\]plants is

    A)                  PEP      

    B)                  PGA

    C)                  RuBP                                   

    D)                  Pyruvic acid

    Correct Answer: A

    Solution :

                     In \[{{C}_{4}}\] plants bundle sheath cells of leaf show Kranz anatomy. In \[{{C}_{4}}\] plants, the \[C{{O}_{2}}\] first accepted in the mesophyll cells by PEP (phosphoenol pyruvate) and form a four carbon compound oxaloacetic acid. Phosphoenol pyruvate \[C{{O}_{2}}\xrightarrow[Corboxylase]{PEP}\]  Oxaloacetic acid In \[{{C}_{3}}\] plants, the carboxylation (addition of\[C{{O}_{2}}\]) of RuBP (Ribulose 1, 5 biphosphate) is catalyzed by an enzyme rubisco to form a 3-carbon compound phosphoglyceric acid (the first stable product of \[{{C}_{3}}\] plants). RuBP \[+C{{O}_{2}}\xrightarrow{Rubisco}\] 3-phosphoglyceric acid Pyruvic acid is the end product of glycolysis During glycolysis one molecule of glucose is breakdown into two molecules of pyruvic acid.


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