A) zero
B) unequal
C) roughly equal
D) exactly equal
Correct Answer: D
Solution :
The centripetal force required to keep the ball in circular motion is \[F=\frac{m{{v}^{2}}}{r}\] where m is mass, v the velocity and r the radius \[\therefore \] \[v=\sqrt{\frac{Fr}{m}}\] \[(\because r=l)\] Given, \[F=25\,N,\] r = 1.96 m, m = 0.25 kg \[\therefore \] \[v=\sqrt{\frac{25\times 1.96}{0.25}}=\sqrt{196}\] \[\Rightarrow \] v = 14 m/sYou need to login to perform this action.
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