A) 50 kg/s
B) 100 kg/s
C) 200 kg/s
D) 400 kg/s
Correct Answer: B
Solution :
The force (F) lifting the rocket is given by \[F={{v}_{r}}\left( \frac{\Delta m}{\Delta t} \right)\] Where \[{{v}_{r}}\] velocity of the gas relative to rocket, \[\frac{\Delta m}{\Delta t}\] is, is rate of change of mass. Given, \[F=Mg=1000\times 10,000\,N\] \[{{v}_{r}}=100\,m/s\] \[\therefore \] \[\frac{\Delta m}{\Delta t}=\frac{F}{{{v}_{r}}}\] \[=\frac{10,000}{100}=100\,kg/s\]You need to login to perform this action.
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