A) cold NaOH
B) \[NaN{{O}_{2}}\] and \[HCl\,(0-{{5}^{o}}C)\]
C) \[SnC{{l}_{2}}\] at \[{{10}^{o}}C\]
D) \[{{N}_{2}}O\] at \[(0-{{5}^{o}}C)\]
Correct Answer: B
Solution :
Diazodsadon : Benzene diazonium chloride is prepared by treating aniline with sodium nitrite and hydrochloric acid at \[{{0}^{o}}C-{{5}^{o}}C\]. This reaction is called diazotisation. \[NaN{{O}_{2}}+HCl\xrightarrow{{}}NaCl+HN{{O}_{2}}\]
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