A) 1.4\[f\]
B) 0.7\[f\]
C) 2\[f\]
D) \[f\]
Correct Answer: B
Solution :
The frequency of a wire is given by \[f=\frac{1}{T}=\frac{1}{2\pi }\sqrt{\frac{g}{l}}\] \[\Rightarrow \] \[f\propto \frac{1}{\sqrt{l}}\] \[\therefore \] \[\frac{f}{f}=\frac{\sqrt{l}}{\sqrt{l}}\] \[\Rightarrow \] \[\frac{f}{f}=\frac{\sqrt{l}}{\sqrt{2l}}=\frac{1}{\sqrt{2}}\] \[\Rightarrow \] \[f=07\,f\]
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