A) decreases
B) increases
C) remains constant
D) None of the above
Correct Answer: B
Solution :
Water is dissociated into hydrogen and hydroxyl ions, as represented by equation \[{{H}_{2}}O{{H}^{+}}+O{{H}^{-}}\] \[K=\frac{[{{H}^{+}}]\,\,[O{{H}^{-}}]}{[{{H}_{2}}O]}\] \[K\,[{{H}_{2}}O]=[{{H}^{+}}]\,\,[O{{H}^{-}}]\] \[{{K}_{w}}=[{{H}^{+}}]\,\,[O{{H}^{-}}]\]where, \[{{K}_{w}}\] is ionic product of water. At \[{{25}^{o}}C\], \[{{K}_{w}}=1\times {{10}^{-14}}\] The value of ionic product of water increases on increasing the temperature, because the degree of ionisation increases, on increasing the temperature.| Temp/\[^{o}C\] | \[{{K}_{w}}\] |
| 25 | \[1\times {{10}^{-14}}\] |
| 60 | \[9.6\times {{10}^{-14}}\] |
| 100 | \[5.5\times {{10}^{-13}}\] |
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