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AMU Medical AMU Solved Paper-2003

  • question_answer
    The correct designation of an electron with \[n=4,\,\,l=3,\,\,m=2\] and \[s=-\frac{1}{2}\] is

    A)  5s                                          

    B)  4s

    C)  4d                                         

    D)  4 \[f\]

    Correct Answer: D

    Solution :

                     Key Idea Principal quantum number (n) determines the main energy level or shell. Azimuthal quantum number \[(l)\] determines the sub-shell. Value of \[(l)\]  0              1              2              3 Sub-shell             s              p             d             f Magnetic quantum number (m) refers to the different orientations of the orbital in space. Spin quantum number (s) describes the spin orientation of the electron. Here,     \[n=4,\,\,l=3,\,\,m=2\] and \[s=\frac{1}{2}\] Therefore, the correct designation of electron is \[4f\].


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