A) \[{{C}_{2}}{{H}_{2}}\]
B) \[{{C}_{6}}{{H}_{6}}\]
C) \[{{C}_{3}}{{H}_{3}}\]
D) \[{{C}_{4}}{{H}_{4}}\]
Correct Answer: B
Solution :
Key Idea Molecular formula \[=\text{ }{{\left( empirical\text{ }formula \right)}_{n}}\] \[n=\frac{molecular\text{ }weight}{empirical\text{ }formula\text{ }weight}\] \[\because \] The empirical formula of compound = CH \[\therefore \] Empirical formula weight = 13 Molecular weight = 78 \[n=\frac{78}{13}=6\] Hence, molecular formula \[=\text{ }{{\left( empirical\text{ }formula \right)}_{n}}\] \[={{(CH)}_{6}}={{C}_{6}}{{H}_{6}}\]
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