AMU Medical AMU Solved Paper-2003

  • question_answer
    If a lens is moved towards the object from a distance of 20 cm to IS cm, the magnification of the image remains the same. The focal length of the lens is

    A)  18.2cm                                

    B)  16.8cm

    C)  17.5cm                                

    D)  15.5cm

    Correct Answer: C

    Solution :

                     From lens formula          \[\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\]where \[f\] is focal length, v the image distance and u the object distance. For convex lens \[\frac{1}{f}=\frac{1}{v}-\frac{1}{(-\mu )}=\frac{1}{v}+\frac{1}{u}\] Multiplying both sides by, u we get                 \[\frac{u}{v}+1=\frac{u}{f}\] \[\Rightarrow \]               \[\frac{u}{v}=\frac{u-f}{f}\]                 or            \[\frac{v}{u}=\frac{f}{u-f}\] or            \[m=\frac{f}{u-f}\] According to question                                 \[{{m}_{1}}=-{{m}_{2}}\]                 \[\therefore \]  \[\frac{f}{{{u}_{1}}-f}=\frac{f}{f-{{u}_{2}}}\]                 \[\Rightarrow \]               \[\frac{f}{20-f}=\frac{f}{f-15}\]                 \[\Rightarrow \]               \[2f=20+15\]                 \[\Rightarrow \]               \[f=\frac{35}{2}=17.5\,\,cm\]    


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