AMU Medical AMU Solved Paper-2003

  • question_answer
    A source of sound of frequency n and a listener approach each other with a velocity equal to \[\frac{1}{20}\] of velocity of sound. The apparent frequency heard by the listener is

    A)  \[\left( \frac{21}{19} \right)n\]                 

    B)  \[\left( \frac{20}{21} \right)n\]

    C)  \[\left( \frac{21}{20} \right)n\]                 

    D)  \[\left( \frac{19}{20} \right)n\]

    Correct Answer: A

    Solution :

                     From Dopplers effect, the perceived frequency (n) is given by                 \[n=\left( \frac{v+{{v}_{o}}}{v-{{v}_{s}}} \right)n\] where v is velocity of sound, \[{{v}_{o}}\] of observer and \[{{v}_{s}}\] of source. Given,   \[{{v}_{o}}=\frac{v}{20},\,\,\,{{v}_{s}}=\frac{v}{20}\] \[\therefore \]  \[n=\left( \frac{v+\frac{v}{20}}{v-\frac{v}{20}} \right)n\] \[\Rightarrow \]               \[n=n\left( \frac{21\,v}{19\,v} \right)=\left( \frac{21}{19} \right)n\]


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