2. Solved Papers
  3. AMU Medical

AMU Medical AMU Solved Paper-2003

  • question_answer
    Two identical capacitors are joined in parallel and charged to a potential V. Then these are separated and connected in series with the positive plate of one connected to the negative of the other. Then the

    A)  potential difference between the plates becomes 2V

    B)   energy stored in the system increases

    C)   charges on the free plates are enhanced

    D)  charges on the plates connected together are destroyed

    Correct Answer: A

    Solution :

                     We know that                 Potential \[V=\frac{energy\,\left( Q \right)}{charge\text{ }\left( q \right)}\] Dimensions of energy \[(Q)=[M{{L}^{2}}{{T}^{-2}}]\] Dimensions of charge (q) = [IT] \[\therefore \] Dimensions of potential \[V=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[IT]}\] Dimensions of potential \[V=[M{{L}^{2}}{{T}^{-3}}{{I}^{-1}}]\]


You need to login to perform this action.
You will be redirected in 3 sec spinner