A) Fission
B) Fusion
C) Both (a) and (b)
D) None of the above
Correct Answer: A
Solution :
The potential on the surface of a ball of radius R, is given by \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{Q}{R}\] Given, \[R=\frac{8}{2}\,cm=\frac{8}{2}\times {{10}^{-2}}m\], \[Q=-4\times {{10}^{-8}}C\] \[V=9\times {{10}^{9}}\times \frac{-4\times {{10}^{-8}}}{4\times {{10}^{-2}}}\] = - 9000 volt
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