A) 75
B) 50
C) 30
D) 25
Correct Answer: C
Solution :
Voltage amplification for a triode valve is given by \[A=\frac{\mu R}{{{r}_{p}}+R}\]where \[{{r}_{p}}\] is plate resistance and R the load resistance. Given, \[{{r}_{p}}=25\,=K\Omega =25\times {{10}^{3}}\Omega \] A = 20 \[R=50\,k\Omega =50\times {{5010}^{3}}\Omega \] \[\therefore \] \[\mu =\frac{A\,({{r}_{p}}+R)}{R}\] \[\therefore \] \[\mu =\frac{20\times (25+50)\times {{10}^{3}}}{50\times {{10}^{3}}}=30\]
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