A) 1.5
B) 2.5
C) 4.5
D) 13.5
Correct Answer: C
Solution :
The radius (R) of the nucleus of any metal is \[R={{R}_{0}}{{A}^{1/3}}\] where A is atomic number, and \[{{r}_{0}}=1.5\] fermi For aluminium A = 27 \[\therefore \] \[R=1.5\times {{(27)}^{1/3}}\] \[R=1.5\times {{(27)}^{1/3}}\] fermi
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