A) \[AgBr\]
B) \[AgCl\]
C) \[AgF\]
D) \[AgI\]
Correct Answer: C
Solution :
Silver fluoride \[(AgF)\] is soluble whereas the\[AgCl\], \[AgBr\] and \[Agl\] are insoluble in water. Abnormal insolubilities of \[AgX\] other than \[AgF\] are due to their high lattice energies on account of strong van der Waals attraction between silver and halides ions in addition to electrostatic attraction between them. On the other hand in \[AgF\] due to smaller number of electrons in \[{{F}^{-}}\] ions, the van der Waals, attraction is weak and hence, lattice energy of \[AgF\] is weak with the result it dissolves in water.
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