A) \[8\sigma \] and \[2\pi \] bonds
B) \[9\sigma \] and \[1\pi \] bond
C) \[9\sigma \]and \[3\pi \] bonds
D) \[9\sigma \] and \[2\pi \] bonds
Correct Answer: D
Solution :
Key Idea A \[C=C\] contains one a and one K-bond, and a \[C\equiv C\] contains one a and two n-bond. The number of a and Ti-bonds in \[C{{H}_{2}}=CH-CH=C{{H}_{2}}\] is as \[H\underset{\sigma }{\mathop{-}}\,\overset{\begin{smallmatrix} H \\ {{|}_{\sigma }} \end{smallmatrix}}{\mathop{C}}\,\overset{\pi }{\mathop{\underset{\sigma }{\mathop{=}}\,}}\,\overset{\begin{smallmatrix} H \\ {{|}_{\sigma }} \end{smallmatrix}}{\mathop{C}}\,\underset{\sigma }{\mathop{-}}\,\overset{\begin{smallmatrix} H \\ {{|}_{\sigma }} \end{smallmatrix}}{\mathop{C}}\,\overset{\pi }{\mathop{\underset{\sigma }{\mathop{=}}\,}}\,\overset{\begin{smallmatrix} H \\ {{|}_{\sigma }} \end{smallmatrix}}{\mathop{C}}\,\underset{\sigma }{\mathop{-}}\,H\] So, there are \[9\sigma \] and \[2\pi \]-bonds are present in \[C{{H}_{2}}=CH-CH=C{{H}_{2}}\]
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