A) \[\text{1}.\text{25}\times \text{l}{{0}^{\text{19}}}\]
B) \[\text{1}.\text{25}\times \text{l}{{0}^{\text{18}}}\]
C) \[\text{3}.\text{125}\times \text{1}{{0}^{11}}\]
D) \[\text{5}\times \text{l}{{0}^{\text{11}}}\]
Correct Answer: B
Solution :
Efficiency \[=\frac{power\text{ }output}{power\text{ }input}\] \[\Rightarrow \] Power input \[=\frac{power\,\,output}{efficiency}\] Given, power output =10 MW, efficiency \[=\frac{25}{100}=0.25\] Power input \[=\frac{10\times {{10}^{6}}}{0.25}=40\times {{10}^{6}}W\] Nuclear fission release 200 MeV energy \[=200\times {{10}^{6}}\times 1.6\times {{10}^{-19}}\] \[=3.2\times {{10}^{-11}}J\] Number of fissions \[=\frac{40\times {{10}^{6}}}{3.2\times {{10}^{-11}}}\] \[=1.25\times {{10}^{18}}\]
You need to login to perform this action.
You will be redirected in
3 sec
