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AMU Medical AMU Solved Paper-2002

  • question_answer
    The temperature of a furnace is \[2327{}^\circ C\] and the intensity of maximum in its spectrum is nearly at \[12000\overset{\text{o}}{\mathop{\text{A}}}\,\]. If the intensity in the spectrum of a star is maximum nearly at \[4800\overset{\text{o}}{\mathop{\text{A}}}\,\], then the surface temperature of the star is

    A) \[767{}^\circ C\]                      

    B) \[1040{}^\circ C\]

    C) \[6500{}^\circ C\]        

    D) \[6227{}^\circ C\]

    Correct Answer: D

    Solution :

                     From Wiens law                                 \[{{\lambda }_{m}}T=\] constant. \[\therefore \]  \[{{\lambda }_{1}}{{T}_{1}}={{\lambda }_{2}}{{T}_{2}}\] Given,   \[{{T}_{1}}={{2327}^{o}}C\]                 \[=2327+273=2600\,K\],                 \[{{\lambda }_{1}}=12000\,\overset{o}{\mathop{A}}\,\],              \[{{\lambda }_{2}}=4800\,\overset{o}{\mathop{A}}\,\] \[\therefore \]  \[{{T}_{2}}=\frac{12000\times 2600}{4800}=6500\,K\] In centigrade T = 6500 - 273                                 \[={{6227}^{o}}C\]


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