AMU Medical AMU Solved Paper-2000

  • question_answer
    For the reaction,\[PC{{l}_{5}}(g)PC{{l}_{3}}(g)+C{{l}_{2}}(g)\]

    A)  \[{{K}_{p}}={{K}_{c}}[RT]\]        

    B)  \[{{K}_{p}}={{K}_{c}}{{[RT]}^{2}}\]

    C)  \[{{K}_{p}}={{K}_{c}}{{[RT]}^{-1}}\]        

    D)  \[{{K}_{p}}={{K}_{c}}\]

    Correct Answer: A

    Solution :

                     Key Idea The relation between \[{{K}_{p}}\] and \[{{K}_{c}}\] is given by \[{{K}_{p}}={{K}_{c}}\,{{(RT)}^{\Delta n}}\]where \[\Delta n=\] difference of stoichiometric coefficients of gaseous product and reactants. Assuming all the reactants and products in gaseous state. For the reaction                 \[aA+bBcC+dD\]                 \[\Delta n=(c+d)-(a+b)\] For the reaction                 \[PC{{l}_{5}}(g)PC{{l}_{3}}(g)+C{{l}_{2}}(g)\]                                 \[\Delta n=2-1=1\] Therefore,          \[{{K}_{p}}={{K}_{c}}{{(RT)}^{1}}\]                                 \[{{K}_{p}}={{K}_{c}}(RT)\]


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