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AMU Medical AMU Solved Paper-2000

  • question_answer
    The oxidation number of chlorine in \[HCl{{O}_{4}}\] is

    A)  +7                                         

    B)  +5

    C)  +3                                         

    D)  -1

    Correct Answer: A

    Solution :

                     \[HCl{{O}_{4}}\](O.N. of H) + (O.N. of Cl) + (O.N. of 0) = 0 Let oxidation number of \[Cl=x\] We know that Oxidation number of \[H=+1\] Oxidation number of \[0=-2\] Therefore, \[+1+x+4\,(-2)=0\]                                 \[1+x-8=0\]                                                 \[x=+7\] So, the oxidation number of chlorine in \[HCl{{O}_{4}}\] is +7.


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