A) \[R-F>R-I>R-Br>R-Cl\]
B) \[R-F>R-Cl>R-Br>R-I\]
C) \[R-I>R-Br>R-Cl>R-F\]
D) \[R-I>R-F>R-Br>R-Cl\]
Correct Answer: C
Solution :
For a general reaction \[R-L+{{B}^{-}}\xrightarrow{{}}\] alkene + \[BH+{{L}^{\Theta }}\] where, \[{{L}^{\Theta }}\] is the leaving group. Rate of cleavage of \[C-X\] bond is in order \[\to -X\to \oplus ={{X}^{-}}\] \[\underset{fastest}{\mathop{I}}\,\,\,\,\,>\,\,\,Br\,\,\,>\,\,\,Cl\,\,\,\,\,>\,\,\,\,\underset{slowest}{\mathop{F}}\,\] So, the ease of the leaving group in alkyl halide is \[-I>-Br>-Cl>-F\] The bond strengths being in order \[C-F>C-Cl>C-Br>C-I\] and amongst the alkyl group the order of reactivity is \[ter>\sec >pri\] But in the given question the alkyl group is the same. So, the reactivity of the alkyl halide is in the following order \[R-I>R-Br>R-Cl>R-F\]
You need to login to perform this action.
You will be redirected in
3 sec
