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AMU Medical AMU Solved Paper-2000

  • question_answer
    The rise in the boiling point of a solution containing 1.8 g of glucose in 100 g of a solvent is \[{{0.1}^{o}}C\]. The molal elevation constant of the liquid is

    A)  0.01 K/m                            

    B)  0.1 K/m

    C)  IK/m                                    

    D)  10 K/m

    Correct Answer: C

    Solution :

                     Key Idea             \[\Delta {{T}_{b}}={{K}_{b}}\times m\]                                 \[{{K}_{b}}=\frac{\Delta {{T}_{b}}}{m}\] Here,     \[\Delta {{T}_{b}}={{0.1}^{o}}C\]                 \[m=\frac{1.8/180}{100/100}=0.1\,m\]                 \[{{K}_{b}}=\frac{0.1}{0.1}\]                 \[{{K}_{b}}=1\,\,K/m\]


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