A) \[E=\frac{\lambda }{p}\]
B) \[E=\frac{h}{\lambda }\]
C) \[E=\frac{h}{p}\]
D) None of these
Correct Answer: D
Solution :
Key Idea According to de-Broglie, the wavelength associated with a particle of mass m, moving with velocity v is given by \[\lambda =\frac{h}{mv}\]where, h = Plancks constant According to Planck the energy of photon is given by \[E=hv\] ... (i) where \[v=\] frequency According to Einstein, mass and energy are related as \[E=m{{c}^{2}}\] ... (ii) From Eqs. (i) and (ii), \[hv=m{{c}^{2}}\] \[\frac{hc}{\lambda }=m{{c}^{2}}\] \[\left( v=\frac{c}{\lambda } \right)\] \[\frac{h}{\lambda }=mc\] \[\lambda =\frac{h}{mc}\] or \[\lambda =\frac{h}{mv}\] or \[\lambda =\frac{h}{p}\] In the question all the relations are incorrect for de-Broglie equation.
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