AMU Medical AMU Solved Paper-2000

  • question_answer
    The temperature of a furnace is \[2324{}^\circ C\] and the intensity is maximum in its radiation spectrum nearly at \[12000\,\overset{\text{o}}{\mathop{\text{A}}}\,\]. If the intensity in the spectrum of a star is maximum nearly at \[4800\,\overset{\text{o}}{\mathop{\text{A}}}\,\]. Then surface temperature of the star is

    A) \[7219.5{}^\circ C\]                             

    B) \[6219.5{}^\circ C\]

    C) \[6319.5{}^\circ C\]                    

    D)  None of these

    Correct Answer: B

    Solution :

    From Wiens displacement law                                 \[{{\lambda }_{m}}T=\] constant Given,   \[{{T}_{1}}={{2324}^{o}}C=2597\,\,K\],                 \[{{\lambda }_{{{m}_{1}}}}12000\,\overset{o}{\mathop{A}}\,\],                 \[{{\lambda }_{{{m}_{2}}}}48000\,\overset{o}{\mathop{A}}\,\] \[\therefore \]  \[{{\lambda }_{{{m}_{1}}}}{{T}_{1}}={{\lambda }_{{{m}_{2}}}}{{T}_{2}}\] \[\Rightarrow \]               \[{{T}_{2}}=\frac{{{\lambda }_{{{m}_{1}}}}}{{{\lambda }_{{{m}_{2}}}}}{{T}_{1}}\]                                \[{{T}_{2}}=\frac{12000}{4800}\times 2597\]                 = 6492.5 K \[\Rightarrow \]               \[{{T}_{2}}={{(6492.5-273)}^{o}}C\]                 \[={{6219.5}^{o}}C\]


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