A) 128
B) 256
C) 64
D) 32
Correct Answer: A
Solution :
For adiabatic expansion \[p{{V}^{\gamma }}=\] constant. Also, volume (V) \[=\frac{Mass\left( M \right)}{density\,\left( \rho \right)}\] \[\therefore \] \[p{{\left( \frac{M}{\rho } \right)}^{\gamma }}\] = constant \[\Rightarrow \] \[\frac{p}{{{\rho }^{\gamma }}}\frac{p}{p\gamma }\] \[\Rightarrow \] \[\frac{p}{p}={{\left( \frac{\rho }{\rho } \right)}^{\gamma }}\] Given, \[\frac{p}{p}=32,\,\,\,\gamma =\frac{7}{5}\] \[\Rightarrow \] \[\frac{p}{p}={{(32)}^{7/5}}\] Also, \[{{2}^{5}}=32\] \[\therefore \] \[\frac{p}{p}={{(2)}^{7}}=128\]
You need to login to perform this action.
You will be redirected in
3 sec
