A) 1.47km/s .
B) 0.94 km/s
C) 1.84 km/s
D) 0.47 km/s
Correct Answer: D
Solution :
Root mean square velocity \[({{v}_{rms}})\] is given by \[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}\]where M is molecular weight, R the gas constant, and T the absolute temperature. Given, \[{{v}_{H}}=1.84\,\,km/s\], \[{{M}_{H}}=2,\,\,\,{{M}_{O}}=32\] \[\frac{{{v}_{H}}}{{{v}_{O}}}=\sqrt{\frac{{{M}_{O}}}{{{M}_{H}}}}\] \[\Rightarrow \] \[\frac{{{v}_{H}}}{{{v}_{O}}}=\sqrt{\frac{32}{2}}=4\] \[\Rightarrow \] \[{{v}_{O}}=\frac{{{v}_{H}}}{4}\] \[=\frac{1.84}{4}=0.47\,\,km/s\]
You need to login to perform this action.
You will be redirected in
3 sec
