A) zero
B) reduced to \[\frac{1}{3}\]
C) also doubled
D) None of these
Correct Answer: D
Solution :
From Plancks law, energy of emitted electrons is E = hv where h is Plancks constant, v the frequency. \[\therefore \] Given, \[{{v}_{2}}=2{{v}_{1}}\] \[\therefore \] \[\frac{{{E}_{2}}}{{{E}_{1}}}=\frac{{{v}_{2}}}{{{v}_{1}}}\] \[\Rightarrow \] \[{{E}_{2}}=\frac{2{{v}_{1}}}{{{r}_{1}}}{{E}_{1}}\] Hence, energy of emitted electrons is also doubled.
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