2. Solved Papers
  3. AMU Medical

AMU Medical AMU Solved Paper-2000

  • question_answer
    The internal resistance of a cell of emf 2 V is 0.10. It is connected to a resistance of 3.9 \[\Omega \] the voltage across the cell will be

    A)  1.95 V                                  

    B)  12.7 V

    C)  1.5 V                                    

    D)  6.71 V

    Correct Answer: A

    Solution :

                     When current is drawn from cell, its emf (E) reduces and potential drop (V) is given by                                 \[V=E-Ir\]                            ... (i) From Ohms law \[I=\frac{E}{R}\]                               ... (ii)                 \[R=3.9\,\,\Omega +0.1\,\,\Omega =4\,\,\Omega \],                 \[E=2\,V,\,\,\,r=0.1\,\,\Omega \] \[\because \]     \[I=\frac{2}{4}=0.5\]                       ... (iii) For Eqs. (i), (ii) and (iii), we get                                 \[V=2-0.5\times 0.1\]     \[\Rightarrow \]               V = 1.95 volt


You need to login to perform this action.
You will be redirected in 3 sec spinner