A) \[8563\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[10818\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[6409\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[12818\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: D
Solution :
For first member of Balmer series \[\frac{1}{{{\lambda }_{1}}}=R\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right)\] ?. (i) For second member of Paschen series \[\frac{1}{{{\lambda }_{2}}}=R\,\,\left( \frac{1}{{{3}^{2}}}-\frac{1}{{{5}^{2}}} \right)\] ?. (ii) Dividing Eq. (i) by Eq. (ii), we get \[\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{\frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}}}{\frac{1}{{{3}^{2}}}-\frac{1}{{{5}^{2}}}}\] \[\Rightarrow \] \[\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{\frac{1}{4}-\frac{1}{9}}{\frac{1}{9}-\frac{1}{25}}\] \[=\frac{5\times 225}{16\times 36}=1.953\] \[\Rightarrow \] \[{{\lambda }_{2}}=1.953\times 6563\] \[=12818\,\overset{o}{\mathop{A}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
