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AMU Medical AMU Solved Paper-2000

  • question_answer
    Energy in Bohrs orbit is given by the \[{{E}_{n}}=-\left( \frac{B}{{{n}^{2}}} \right)\] where n is principal quantum number and \[\text{B}=\text{2}.\text{2}\times \text{1}{{0}^{\text{18}}}\text{ J}.\]The frequency of radiation when an electron jumps from the third orbit to the second orbit is \[\left( h=6.6\times \text{1}{{0}^{-34}}\text{ Js} \right)\]

    A)  \[\text{4}.\text{6}\times \text{1}{{0}^{\text{14}}}\text{ Hz}\]  

    B)   \[\text{2}.\text{3}\times \text{1}{{0}^{\text{14}}}\text{ Hz}\]

    C)  \[\text{8}.\text{2}\times \text{l}{{0}^{\text{14}}}\text{Hz}\]    

    D)  None of these

    Correct Answer: A

    Solution :

                     From Bohrs concept, the frequency v is given by                 \[E=hv={{E}_{2}}-{{E}_{1}}\] \[\Rightarrow \]               \[hv=B\left[ \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right]=\frac{5B}{36}\] \[\Rightarrow \]               \[v=\frac{5B}{36h}\]                 \[=\frac{5}{36}\times \frac{2.2\times {{10}^{-18}}}{6.6\times {{10}^{-34}}}\] \[\Rightarrow \]               \[v=4.6\times {{10}^{14}}Hz\].


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