A) \[9(\beta -\alpha )\]
B) \[5\alpha -4\beta \]
C) \[5\beta -4\alpha \]
D) \[\beta -\alpha \]
Correct Answer: C
Solution :
: \[k=\]force constant of spring = force/length. Increase in length due to force = force/\[k=\frac{F}{k}\]Original length\[=L\] \[\therefore \] Final length\[=L+\frac{F}{k}\] \[\therefore \]\[\beta =L+\frac{5}{k}\] \[\alpha =L+\frac{4}{k}\] \[\therefore \]\[\beta -\alpha =\frac{I}{k}\] ?..(i) \[\therefore \]\[\beta =L+5(\beta -\alpha )\] or \[\beta =L+5\beta -5\alpha \] or \[5\alpha -4\beta =L\] When force\[=9\text{ }N,\]final length be\[l\]. \[l=L+\frac{9}{k}=(5\alpha -4\beta )+9(\beta -\alpha )\] \[=5\alpha -4\beta +9\beta -9\alpha =5\beta -4\alpha \]You need to login to perform this action.
You will be redirected in
3 sec