AMU Medical AMU Solved Paper-1998

  • question_answer
    The brown ring formation in the test for nitrate is due to

    A)  \[{{[Fe({{H}_{2}}O){{(NO)}_{5}}]}^{2+}}\]

    B)  \[{{[Fe{{({{H}_{2}}O)}_{5}}(NO)]}^{2+}}\]

    C)  \[Fe{{(N{{O}_{3}})}_{3}}\]

    D)  \[{{[Fe{{({{H}_{2}}O)}_{5}}(N{{O}_{2}})]}^{2+}}\]

    Correct Answer: B

    Solution :

    : Ring test: \[NaN{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\to NaHS{{O}_{4}}+HN{{O}_{3}}\] \[6FeS{{O}_{4}}+2HN{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\to 3F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+\] \[4{{H}_{2}}O+2NO\] \[[Fe{{({{H}_{2}}O)}_{6}}]S{{O}_{4}}.{{H}_{2}}O+NO\to \] \[\underset{Brown\text{ }ring}{\mathop{[Fe{{({{H}_{2}}O)}_{5}}NO]S{{O}_{4}}}}\,+2{{H}_{2}}O\]


You need to login to perform this action.
You will be redirected in 3 sec spinner