A) at rest
B) moving in the direction of the field
C) moving in a direction making an angle of 45 to the field
D) moving perpendicular to the direction of the field
Correct Answer: D
Solution :
: Force on charged particle\[=Bqv\sin \theta \] where\[\theta =\]angle of path of motion with field B. The force is maximum when\[(\sin \theta )\]is maximum \[\therefore \]\[\theta =90{}^\circ \].
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