A) \[\overrightarrow{E}=\hat{i}(2xy-{{z}^{3}})+\hat{j}x{{y}^{2}}+\hat{k}3{{z}^{2}}x\]
B) 10kg
C) 20kg
D) \[2\times {{10}^{4}}J{{T}^{-1}}\]
Correct Answer: D
Solution :
Key Idea According to Newton?s second law of motion, force = mass \[=-k(x+a)\]acceleration. Here,\[=k(x+a)\] \[k,{{k}_{0}},{{k}_{1}}\] \[9\times {{10}^{17}}\] \[3\times {{10}^{16}}\] \[9\times {{10}^{15}}\]\[3\times {{10}^{19}}\]
You need to login to perform this action.
You will be redirected in
3 sec
