A) \[93\,kJ\,mo{{l}^{-1}}\]
B) \[-245\,kJ\,mo{{l}^{-1}}\]
C) \[-93\,kJ\,mo{{l}^{-1}}\]
D) \[245\,kJ\,mo{{l}^{-1}}\]
Correct Answer: C
Solution :
Key Idea: \[\Delta {{H}_{reaction}}=\Sigma \]energy of reactant \[-\Sigma \]Bond energy of product Here, \[\Delta {{H}_{H-H}}=434\,kJ\,mo{{l}^{-1}}\] \[\Delta {{H}_{Cl-Cl}}=242\,kJ\,mo{{l}^{-1}}\] \[\Delta {{H}_{H-Cl}}=431\,kJ\,mo{{l}^{-1}}\] \[\because \] \[\frac{1}{2}{{H}_{2}}+\frac{1}{2}C{{l}_{2}}\xrightarrow[{}]{{}}HCl\] \[\Delta {{H}_{reaction}}=\frac{1}{2}\Delta {{H}_{H-H}}+\frac{1}{2}\Delta {{H}_{Cl-Cl}}-\Delta {{H}_{H-Cl}}\] \[=\frac{1}{2}\times 434+\frac{1}{2}\times 242-431\] \[=217+121-431\] \[=-93\,kJ\,mo{{l}^{-1}}\]
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