NEET AIPMT SOLVED PAPER SCREENING 2008

  • question_answer
    In an AC circuit the emf (e) and the current (i) at any instant are given respectively by \[e={{E}_{0}}\sin \omega t\] \[i={{I}_{0}}\sin (\omega t-\phi )\] The average power in the circuit over one cycle of AC is

    A) \[\frac{{{E}_{0}}{{I}_{0}}}{2}\]   

    B)        \[\frac{{{E}_{0}}{{I}_{0}}}{2}\sin \phi \]

    C) \[\frac{{{E}_{0}}{{I}_{0}}}{2}\cos \phi \]

    D)        \[{{E}_{0}}{{I}_{0}}\]

    Correct Answer: C

    Solution :

                    Key Idea: The power is defined as the rate at which work is being done in the circuit. Power = rate of work done in one complete cycle. or\[{{P}_{av}}=\frac{W}{T}\]or\[{{P}_{av}}=\frac{({{E}_{0}}{{I}_{0}}\cos \phi )T/2}{T}\] or\[{{P}_{av}}=\frac{{{E}_{0}}{{I}_{0}}\cos \phi }{2}\]where \[\cos \phi \] is called the power factor of an AC circuit.


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