A) \[1.81\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[2.10\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[2.92\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[1.27\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: D
Solution :
Atomic radius is the distance between two nearest neighbours. For fee crystal Atomic radius \[=\frac{1}{2\sqrt{2}}\times \]lattice parameter or\[r=\frac{a}{2\sqrt{2}}\]or\[r=\frac{3.6}{2\sqrt{2}}{\AA}=1.27{\AA}\]
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