NEET AIPMT SOLVED PAPER SCREENING 2007

  • question_answer
                    Which one of the following on treatment with 50% aqueous sodium hydroxide yields the corresponding alcohol and acid?                                                                                                                                            

    A)                 \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}CHO\]

    B)                 \[{{C}_{6}}{{H}_{5}}CHO\]

    C)                 \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO\]

    D)                 \[\begin{align}   & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\  & C{{H}_{3}}-\overset{||}{\mathop{C}}\,-C{{H}_{3}} \\ \end{align}\]

    Correct Answer: B

    Solution :

                    Aldehydes which do not have any \[\alpha \]-hydrogen atom when heated with a cone, solution of NaOH undergo a simultaneous oxidation and reduction (disproportionation) forming a salt of carboxylic acid and alcohol called Cannizaro reaction)                 \[2{{C}_{6}}{{H}_{5}}CHO+NaOH\] \[\xrightarrow[{}]{{}}\] \[\underset{benzyl\,alcohol}{\mathop{{{C}_{6}}{{H}_{5}}C{{H}_{2}}OH}}\,+\underset{sodium\,benzoate}{\mathop{{{C}_{6}}{{H}_{5}}COONa}}\,\]


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