A) 16
B) 40
C) 54
D) 4
Correct Answer: C
Solution :
The resistances of \[6\,\,\Omega \] and \[3\,\,\Omega \] are in parallel in the given circuit, their equivalent resistance is \[\frac{1}{{{R}_{1}}}=\frac{1}{6}+\frac{1}{3}=\frac{1+2}{6}=\frac{1}{2}\] or \[{{R}_{1}}=2\,\Omega \] Again, R, is in series with \[4\,\,\Omega \] resistance, hence \[R={{R}_{1}}+4=2+4=6\,\Omega \] Thus, the total power dissipated in the circuit Here, V = 18V, R = 6\[\Omega \] Thus, \[P=\frac{{{(18)}^{2}}}{6}=54\,W\]
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