A) the compound is certainly a chiral
B) the compound is certainly meso
C) there is no compound in die solvent
D) the compound may be a racemic mixture
Correct Answer: D
Solution :
An optically active compound rotate plane polarized light. But due to some external compensation (heat, light, catalyst, solvent etc), the optically active compound loss their optical activity. The compound then exist as recemic mixture i.e., both d and I form are present in solution due to some intramolecular rearrangement. So, there is no rotation of plane polarised light and compound does not have an asymmetric centre and when it again forms the symmetric centre both d- and l forms are obtained in equal amount.
You need to login to perform this action.
You will be redirected in
3 sec
