A) \[SC{{l}_{4}}\]
B) \[SO_{4}^{2-}\]
C) \[PO_{4}^{3-}\]
D) \[NH_{4}^{+}\]
Correct Answer: A
Solution :
\[SC{{l}_{4}}\] is not isostructural of \[SiC{{l}_{4}}\] because it shows square planar structure due to involvement of repulsion between lone pair and bond pair of electrons. \[SO_{4}^{2-}\] shows tetrahedral structure due to \[s{{p}^{3}}\] hybridisation \[PO_{4}^{3-}\] shows tetrahedral structure due to \[s{{p}^{3}}\] hybridisation \[NH_{4}^{+}\] shows tetrahedral structure due to \[s{{p}^{3}}\] hybridisation
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