A) \[1.0\times {{10}^{-6}}M\]
B) \[1.0525\,\times {{10}^{-7}}\,M\]
C) \[9.525\,\times {{10}^{-8}}\,M\]
D) \[1.0\times {{10}^{-8}}M\]
Correct Answer: B
Solution :
In aqueous solution of \[{{10}^{-8}}\] M HCl, \[[{{H}^{+}}]\] is based upon the concentration of \[{{H}^{+}}\] ion of \[{{10}^{-8}}\] M HCl and concentration of \[{{H}^{+}}\] ion of water \[K{{ & }_{w}}\] of \[{{H}_{2}}O={{10}^{-14}}\,=[{{H}^{+}}]\,\,{{[OH]}^{-}}\] or \[[{{H}^{+}}]\,={{10}^{-7}}\,M\] (due to its neutral behaviour) So, in aqueous solution of \[{{10}^{-8}}\,M\,HCl\], \[[{{H}^{+}}]\,=[{{H}^{+}}]\,\] of HCl + \[[{{H}^{+}}]\] of water \[={{10}^{-8}}+{{10}^{-7}}=11\times {{10}^{-8}}\,M\] \[\approx \,1.10\times {{10}^{-7}}\,M\] Hence, answer is nearer to (b).
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