A) \[3d_{{{x}^{2}}-{{y}^{2}}}^{1},\,3d_{{{z}^{2}}}^{1},\,3d_{xz}^{1}\]
B) \[3d_{xy}^{1},\,3d_{{{x}^{2}}-{{y}^{2}}}^{1},\,3d_{yz}^{1}\]
C) \[3d_{xy}^{1},\,3d_{zy}^{1},\,3d_{xz}^{1}\]
D) \[3d_{xy}^{1},\,3d_{yz}^{1},\,3d_{{{z}^{2}}}^{1}\]
Correct Answer: C
Solution :
Magnetic moment \[(\mu )=\sqrt{n(n+2)}\,BM\] or \[3.83=\sqrt{n(n+2)}\,\] or \[3.83\times 3.83={{n}^{2}}+2n\] \[14.6689={{n}^{2}}+2n\] on solving this, we get n = 3 Hence, number of unpaired electrons in d-sub-shell of penultimate shell of chromium (Cr = 24). So, the configuration of chromium ion is \[C{{r}^{3+}}\,=1{{s}^{2}},\,2{{s}^{2}}\,2{{p}^{6}},\,3{{s}^{2}}\,3{{p}^{6}}\,3{{d}^{3}}\] In \[[Cr{{({{H}_{2}}O)}_{6}}]C{{l}_{2}}\] oxidation state of Cr is +3) Hence, in \[3{{d}^{3}}\] the distribution of electrons \[3d_{xy}^{1},\,3d_{yz}^{1},\,3d_{zx}^{1},\,3d_{{{x}^{2}}-{{y}^{2}}}^{0},3d_{{{z}^{2}}}^{0}\]
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