NEET AIPMT SOLVED PAPER SCREENING 2006

  • question_answer
                    A black body at \[{{1227}^{o}}C\] emits radiations with maximum intensity at a wavelength of \[5000\,\overset{o}{\mathop{A}}\,\]. If the temperature of the body is increased by \[{{1000}^{o}}C\], the maximum intensity will be observed at:

    A)                                                                                                                                                                                            \[4000\overset{o}{\mathop{\text{A}}}\,\]

    B)                 \[5000\,\overset{o}{\mathop{A}}\,\]

    C)                 \[6000\,\overset{o}{\mathop{A}}\,\]

    D)                 \[3000\,\overset{o}{\mathop{A}}\,\]

    Correct Answer: D

    Solution :

                    Key   Idea: The product of wavelength corresponding to maximum intensity of radiation and temperature of the body in Kelvin is constant. According to Wien's law                 \[{{\lambda }_{m}}T\]= constant (say b)                 where \[{{\lambda }_{m}}\] is wavelength corresponding to maximum intensity of radiation and T is temperature of the body in Kelvin. \[\therefore \frac{{{\lambda }_{m'}}}{{{\lambda }_{m}}}=\frac{T}{T'}\] Given,   \[T=1227+273=1500\,K,\]                 \[T'=1227+1000+273=2500\,K\]                 \[{{\lambda }_{m}}=5000\,{\AA}\]                 Hence,  \[{{\lambda }_{m'}}=\frac{1500}{2500}\times 5000=3000\,{\AA}\]


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