A) \[250\,\,g\,mo{{l}^{-1}}\]
B) \[300\,\,g\,mo{{l}^{-1}}\]
C) \[350\,\,g\,\,mo{{l}^{-1}}\]
D) \[200\,\,g\,\,mo{{l}^{-1}}\]
Correct Answer: B
Solution :
\[10\,g\,per\,d{{m}^{3}}\] of urea is isotonic with 5% solution of a non-volatile solute. Hence, between these solution osmosis is not possible so their molar concentrations are equal to each other. Thus, molar concentration of urea solution \[=\frac{10\,g/d{{m}^{3}}}{Mol.\,wt.\,of\,urea}\] \[=\frac{10}{60}\,M=\frac{1}{6}\,M\] Molar concentration of 5% non-volatile solute \[=\frac{50\,g/d{{m}^{3}}}{mol.\,wt.\,of\,non-volatile\,solute}\] \[=\frac{50}{m}\,M\] Both solutions are isotonic to each other, therefore \[\frac{1}{6}=\frac{50}{m}\] \[orm=50\times 6=300\,g\,mo{{l}^{-1}}\]
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