NEET AIPMT SOLVED PAPER SCREENING 2006

  • question_answer
                                    When a charged particle moving with velocity \[\vec{v}\] is subjected to a magnetic field of induction \[\vec{B}\], the force on it is non-zero. This implies that:                                                                                                                              

    A)                  angle between \[\vec{v}\] and \[\vec{B}\] is necessarily 90°

    B)                  angle between \[\vec{v}\] and \[\vec{B}\] can have any value other than 90°

    C)                  angle between \[\vec{v}\] and \[\vec{B}\] can have any value other than zero and 180°

    D)                 angle between \[\vec{v}\] and \[\vec{B}\] is either zero or \[{{180}^{o}}\]

    Correct Answer: C

    Solution :

                    When a charged particle q is moving in a uniform magnetic field \[\vec{B}\] with velocity \[\vec{v}\] such that angle between \[\vec{v}\] and \[\vec{B}\] be \[\theta \], then due to interaction between the magnetic field produced due to moving charge and magnetic field applied, the charge q experiences a force which is given by                 \[F=qvB\sin \theta \] If             \[\theta ={{0}^{o}}\]or \[{{180}^{o}}\], then sin \[\theta =0\] \[\therefore \]  \[F=qvB\sin \theta \]                 Since, force on charged particle is non-zero, so angle between \[\vec{v}\] and \[\vec{B}\] can have any value other than zero and \[{{180}^{\text{o}}}\].


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